我好像在哪里见过你

main() {inti=560,h,m; h=i/60; m=i-60*h printf(“%d分钟?%d小时%d分钟”,i,h,m);} 结果为?求解? #include void main( ) { int x=1,y=0,a=0,b=0; switch(x) { case 1:switch(y) { case 0:a++;能不能帮我详细解释一下这个程序的运行过程及结果#include void main( ){ int x=1,y=0,a=0,b=0;switch(x){ case 1:switch(y){ case 0:a++; break;case #include void main() { int x=2,y; switch(x) { case 1:y=x ; break; case 2:y=-x ; case 3:y=x*3 ; break;case 4:y=4*x;printf(“%d\n”,y);} #include main() { int s=0,k; for(k=7;k>=0;k--) { switch(k) { case 1: case 4: case 7: s++; b#includemain(){ int s=0,k;for(k=7;k>=0;k--){ switch(k){ case 1:case 4:case 7: s++; break;case 2;case 3;case 6; break;case 0:case 5: s+=2; break;}}printf("s= 有以下程序#include main() { int c[6]={10,20,30,40,50,60},*p,*s; p=a; s=&c[5]; printf("%d\#includemain(){ int c[6]={10,20,30,40,50,60},*p,*s;p=a; s=&c[5];printf("%d\n",s-p);}为什么答案是5?不是50么? #include "stdio.h" #include "conio.h" struct n {int x,y;} d[2]={1,2,3,4}; main() {struct n *p=d; pr struct ord {int x,y;}dt[2]={1,2,3, #include int main(){ int x=0,y=0; while(x #include main() { struct node{int n;struct node *nest;} *p;#includemain(){struct node{int n;struct node *nest;} *p;struct node x[3]={{2,x+1},{4,x+2},{6,NULL}};p=x;printf("%d\n",p->n);printf("%d\n",p->next->n);} #include main() { int a=1,b=2,c=3,d=4,m=5,n=6; a=(m=a>b)&&(n=c>d)||++a==b--; printf("%d %d#includemain(){int a=1,b=2,c=3,d=4,m=5,n=6;a=(m=a>b)&&(n=c>d)||++a==b--;printf("%d %d %d %d\n",a,b,m,n);}为何是1 1 0 而不是0 1 0 a=(m=a>b)&&(n=c>d)||++a== #include main() { int a=1,b=2,c=3; c=(a+=a+2),(a=b,b+3); printf("%d,%d,%d\n",a,b,c); }这个程序的运行结果中,c的值为什么是4,不是5,求详细解释 #include void fun(int p) { int d=2; p=d++; printf(“%d”,p);} main() { int a=1; fun(a); printf(“%d #include int d=1; void fun (int p) { int d=5 ; d+=p++; printf( "%d " ,d ) ; }main (){ int a=3 ;fun(a);d+=a++;printf("%d\n" ,d );} #include void fun(int x) { if(x/2>0)fun(x/2); printf("%d",x); } main() { fun(3);printf("\n");}相关知识点：递归调用 #include void fun(int x) { x=20; } main() { int x=10; fun(x); printf("x=%d\n",x); }#includevoid fun(int x){x=20;}main(){int x=10;fun(x);printf("x=%d\n",x);} #include void fun(char c) {if(c>'x') fun(c-1); printf("%c",c); } main() {fun('z');} #include main() { int a=0; if(1) a=3; if(0) a=4; else a=5;printf("%d",a);}这语句怎么看不懂.if语句执行哪个?. #include void main( ) { int k=-3; if (k #include main(){int a=1,b=0; if(!a)b++; else if (a==0) if(a) b+=2; else b+=3; printf(b) #include fun(int x) { if(x/2>0)fun(x/2); printf("%d",x); } main() { fun(6); printf("\n"); 这是个递归的程序.当x/2>0时,进行递归.执行fun(6)的时候,会一次执行fun(6)->fun(3)->fun(1).到fun(1)时,x/2不大于0了,开始依次返回, #include void main() { int a=21,b=11; printf("%d\n",--a+b,--b+a); } #include void main() { int k=-1; printf("%d,%u\n",k,k); }尤其是无符号类型的输出问题 void main() { int x=0,y=5,z=3; while(z-->0&&++x void main(){int x=1,y=3,z=5;printf("%d",z>y>x);}为什么答案是0. #include"stdio.h" #define MA(x) x*(x-1) void main() { int a=1,b=2; printf("%d\n",MA(1+a+b)); } #include Int main(void ) { int a = 5,b = 4,x,y; x = 2 * a++ ; printf("a=%d,x=%d\n",a, #include void f(int*x,int y) {*x=y+1;y=*x+2;} main() {int a=2,b=2; f(&a,b); printf("%d\n%d"#includevoid f(int*x,int y){*x=y+1;y=*x+2;}main(){int a=2,b=2;f(&a,b);printf("%d\n%d",a,b);} #include "stdio.h"void main(){int x=3,y=5; if (x=y-4) printf("*"); else printf("#"); }C语言.那个判断x=y-4是什么意思? # include void main() { int y=10; while(y--); printf("y=%d",y); } # include void p(int *x,int y){ ++*x; y=y+2; } void main() { int x=2,y=3; p(&y,y); printf("# includevoid p(int *x,int y){++*x;y=y+2;}void main(){int x=2,y=3;p(&y,y);printf("%d#%d",x,y);} #define f(a,b,x) a*x+b #include void main() printf("%d,%d\n",f(3,2,1),f(6,5,f(3,2,1))) 5减0.64乘八分之七除以四 脱吃