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你能用3个同样大小的等边三角形组成一个图案,使该图形有5个三角形吗? 英语翻译English learning requires various English language materials beyond what is in the text books.不是翻译哦,是理解,用英文回答的 英语翻译Students' reading comprehension will be improved only if English language teachers train them to analyze sentences and enlarge their vocabulary.补充一句，我觉得这句话的理解是错误的吧，可是试卷上只是说给出我 英语翻译The society would benefit from a ban on all forms of advertising because it serves no useful purpose,and can even be damaging. It was 1969 ________ he was A.that B.in that C.when D.which 改错别字,语文 There's always one who you care most.And the one who you missed. 语文修改错别字无暇翡翠 哪个字错了 七年级上册生物第三单元的第三章的练习答案 是课文的 x+y=5cosα+5sinα为什么等于5√2sin(α+π/4), 生物学七年级上册第三单元本章学到了什么答案 你能用3个同样大小的等边三角形组成一个图案,使该图案有5个三角形吗?这道题的思路和答题想法 怎样将三个等边三角形拼成一个图案,使这个图案有五个三角形十万火急! The Rules for Gift GivingYou should be careful in giving gifts . Never give a gift during a job interview or before a business meeting Gifts are usually given during special holidays, or on occasions to swow thanks for special intations When you a 请翻译："where bending the rule is the rule", 英语翻译I was a single parent of four small children,working at a minimum-wage job.Money was always tight,but we had a roof over our heads,food onthetable,clothes on our backs,and if not a lot,always enough.My kids told me that in those days they 关于时差的问题 英语翻译The basic rule to remember is to include something from every food group at each meal using the suggested proportions. 关于地转偏向力 给我找点初二历史题（第一单元的）谢谢 在△OAB中,OA→＝(2cosα,2sinα),OB→＝(5cosβ,5sinβ),若OA→•OB→＝－5,则S△AOB的值为 已知在△OAB（O为原点）中,OA=(2cosα,2sinα),OB=(5cosβ,5sinβ),若OA*OB=-5,则S△AOB的值为 α∈（0,π/3）,β∈（π/6,π/2)且α、β满足5√3sinα+5cosα=8,√2sinβ+√6cosβ=2,求cos(2α－β) ---- is different in different countries.a.gift to give b .gift giving Gift giving is different in different countries.此处为什么填give 的ing形式呀? Gift _ is different in different countries.A give B given C giving D to give选择理由 c＜b＜0＜a,化简|a+c|-|a-b-c|+2|b-a|-|b+c| a＜b＜0＜c,化简|a-b|+|a-c|+|b|+|c|=多少正确无误 When i will go in china,i will give you a gift for you.Your friend 速求英文翻译 化简：-|a|+|b|-|0|-|c|b＜0,a＜b,c＞0 a 根据b