求化简这道题求化简这道题
求化简这道题先用二倍角公式,再和差化积y=1+2(sin(2x-π/3))
f(x)=2sin^2(pi/4+x)-√3cos2x=[1-cos(2(pi/4+x)]-根号3 cos2x=1-cos(pi/2+2x)-根号3cos2x=1+sin2x-根号3cos2x=1+2[1/2sin2x-根号3 /2 cos2x]=1+2sin(2x-60)