y=sin(x+1) 求y'(0)
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y=sin(x+1) 求y'(0)
y=sin(x+1) 求y'(0)
y=sin(x+1) 求y'(0)
y'=cos(x+1)*(x+1)'=cos(x+1)
所以y'(0)=cos(0+1)=cos1
y=sin(x+1) 求y'(0)
y=sin(x+1) 求y'(0)
y=sin(x+1) 求y'(0)
y'=cos(x+1)*(x+1)'=cos(x+1)
所以y'(0)=cos(0+1)=cos1