已知loga2/3/已知loga2/3/<1,求a取值范围
已知loga2/3/0loga(2/3)所以2/3>aa>1,增函数loga(2/3)所以2/3所以01
0loga(2/3)所以2/3>aa>1,增函数loga(2/3)所以2/3所以01