(x+y)(x+y+2)-3因式分解
(x+y)(x+y+2)-3因式分解
(x+y)(x+y+2)-3因式分解
(x+y)(x+y+2)-3因式分解
(x+y)(x+y+2)-3
=(x+y)[(x+y)+2]-3
=(x+y)^2+2(x+y)-3
=[(x+y)+3][(x+y)-1]
=(x+y+3)(x+y-1)
原式
=(x+y)^2+2(x+y)-3
=(x+y+3)(x+y-1)
把x+y看成一个整体就行了
希望可以帮到你,请采纳
(x+y)(x+y+2)-3
=(x+y)^2+2(x+y)-3
=(x+y-1)(x+y+3)
这就是最简的吧你要是非要再算,就这个,我发了图片