(a+1)²+√(7+b)=0,则a+b=
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(a+1)²+√(7+b)=0,则a+b=
(a+1)²+√(7+b)=0,则a+b=
(a+1)²+√(7+b)=0,则a+b=
—8
a+1=0 a=-17+b=0 b=-7所以a+b=-8
a=-1 b=-7 a+b= -8
(a+1)²+√(7+b)=0,则a+b=
(a+1)²+√(7+b)=0,则a+b=
(a+1)²+√(7+b)=0,则a+b=
—8
a+1=0 a=-17+b=0 b=-7所以a+b=-8
a=-1 b=-7 a+b= -8