求不定积分,被积函数为(sin(x)^2+1)^(1/2)

来源:学生作业帮助网 编辑:作业帮 时间:2024/06/05 03:44:34

求不定积分,被积函数为(sin(x)^2+1)^(1/2)
求不定积分,被积函数为(sin(x)^2+1)^(1/2)

求不定积分,被积函数为(sin(x)^2+1)^(1/2)
(sin(x)^2+1)^(1/2)
原式=|根号2(sin0.5x2+cos0.5x2)|=根号2|sin(0.5x2+0.25π)|
剩下的应该会了吧~