1/2[1/3(1-1/4x)]≥1.

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/30 07:05:36

1/2[1/3(1-1/4x)]≥1.
1/2[1/3(1-1/4x)]≥1.

1/2[1/3(1-1/4x)]≥1.
1/2[1/3(1-1/4x)]>=1
1/3(1-1/4x)>=2
1-1/4x>=6
1/4x

1/2[1/3(1-1/4x)]>=1
1/3(1-1/4x)>=2
1-1/4x>=6
1/4x<=1-6=-5
x<=-20

1/2[1/3(1-1/4x)]>=1
1/3(1-1/4x)>=2
1-1/4x>=6
1/4x<=1-6=-5
x<=-20

*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || 解分式不等式(x+2)/(x+1)+(x+3)/(x+2)≥(x+1)/x+(x+4)/(x+3) x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4 x^5-x^4+x^3-x^2+x-1 已知x=2π+1.求(X-1)+(X-2)+(X-3)+(X-4)+(X-5)+(X-6)+(X-7)+(X-8)+(X-9)+(X-10) 求一个数独答案X X X 9 X X X 8 2 X 6 3 X X 1 4 X 99 X 8 X X X X X XX X X 6 7 X 3 X XX 4 6 X 5 X 2 9 XX X 7 X 2 3 X X XX X X X X X 7 X 17 X 4 3 X X 6 2 X6 3 X X X 7 X X X 一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X 填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x 难倒爱因斯坦的九宫格X 7 X | X 8 1 | X X X |X X X | X 4 X | 7 5 9 |X X 5 | 7 X 9 | X 1 4 |5 X X | X X 8 | 3 9 X |3 9 6 | 4 X 7 | X X 2 |X 8 7 | 9 X X | X X X |4 X X | 6 X 5 | X X X | X X 4 | X X 1 |2 X X | X X X | X X X | X 3 X | X X X |X 6 七年级下册政治复习提纲(山东人民出版社)第五单元是 青春的脚步 青春的气息别弄错了啊!格式:X X X X X X X X X 1、X X X X X X X X X X.2、X X X X X X X X X.3、X X X X X X X X X X X. 关于极限1.lim((x^-1) + (x^-4))/((x^-2) - (x^-3)) x-> 正无穷2.lim ((e^x) - (e^-x))/((e^x) + (e^-x)) x-> 负无穷 如下9*9宫图如何填x x x 1 x x x 2 9x x 5 x x x x x 4x 6 8 x x x x x xx x x 7 x x 5 x xx 2 x x 6 x x 8 xx x 3 x x 9 x x xx x x x 5 x 1 6 x 4 x x x 3 x x x x 7 x x x x 2 x x x lim(x+1)^x+1(x+3)^x+3/x^2x+4 x趋于无穷 计算:[(x^2 - 4)/(x^2 - x - 6) + (x+2)/(x-3)] / (x+1)/(x-3) a+x/x+1 ,x/x^2-2x-3 ,a/x^2+4x+3 (x-3/x-2)-(x-2/x-1)=(x-5/x4) -(x-4/x-3) [x^2+2x-8/x^3+2x^2+x]÷[(x-2/x)×(x+4/x+1)]化简[x^2+2x-8/x^3+2x^2+x]÷[(x-2/x)×(x+4/x+1)]化简 (x-1)/(x+3x+2)+6/(2+x-x)-(10-x)/(4-x)