1/(x+4)+1/(x+5)=1/(x+6)+1/(x+3)求解

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1/(x+4)+1/(x+5)=1/(x+6)+1/(x+3)求解
1/(x+4)+1/(x+5)=1/(x+6)+1/(x+3)求解

1/(x+4)+1/(x+5)=1/(x+6)+1/(x+3)求解
1/(x+4)+1/(x+5)=1/(x+6)+1/(x+3)
1/(x+5)-1/(x+6)=1/(x+3)-1/(x+4)
1/[(x+5)(x+6)]=1/[(x+3)(x+4)]
(x+5)(x+6)=(x+3)(x+4)
x²+11x+30=x²+7x+12
x²+11x-x²-7x=12-30
4x=-18
x=-9/2