作业帮(x+y)^2-4(x+y-1)^2怎么分解因式?,
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(x+y)^2-4(x+y-1)^2怎么分解因式?,
(x+y)^2-4(x+y-1)^2怎么分解因式?,
(x+y)^2-4(x+y-1)^2怎么分解因式?,
(x+y)^2-4(x+y-1)^2
=(x+y)^2-[2(x+y-1)]^2
=[x+y+2x+2y-2][x+y-2x-2y+2]
=[3x+3y-2][-x-y+2]
错了吧
是(x+y)^2-4(x+y-1)
=(x+y)^2-4(x+y)+4
=(x+y-2)^2
(x+y)^2-4(x+y-1)^2
=(x+y+2x+2y-2)(x+y-2x-2y+2)
=(3x+3y-2)(2-x-y)
(x+y)^2-4(x+y-1)^2
=(x+y)^2-[2(x+y-1)]^2
=[x+y+2x+2y-2][x+y-2x-2y+2]
=[3x+3y-2][-x-y+2]
(x+y)^2-4(x+y-1)^2
=(x+y)^2-[2(x+y-1)]^2
=[x+y+2x+2y-2][x+y-2x-2y+2]
=[3x+3y-2][-x-y+2]
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