当x=（ “）时,代数式（x-3)²的值是16 a+b=4,ab=1,则2a+3ab+2b等于

当x=（ “）时,代数式（x-3)²的值是16 a+b=4,ab=1,则2a+3ab+2b等于
当x=（ “）时,代数式（x-3)²的值是16 a+b=4,ab=1,则2a+3ab+2b等于

当x=（ “）时,代数式（x-3)²的值是16 a+b=4,ab=1,则2a+3ab+2b等于
(x-3)²=16 x-3=±4 x=7或x=-1
2a+3ab+2b=2a+2b+3ab=2(a+b)+3ab 根据已知得原式=11

X=7或-1 11

因为（x-3)²=16
所以 x-3=±4
所以 x=7或-1
2a+3ab+2b=2（a+b）+3ab=2*4+3*1=11