(1)[(2y+1)(2y-1)]^2 (2)(x+y)(x^2+y^2)(x-y)(x^4+y^4) (3)(2x+y+z)(y-2x-z)

来源：学生作业帮助网编辑：作业帮时间：2024/05/11 19:53:32

(1)[(2y+1)(2y-1)]^2 (2)(x+y)(x^2+y^2)(x-y)(x^4+y^4) (3)(2x+y+z)(y-2x-z)
(1)[(2y+1)(2y-1)]^2 (2)(x+y)(x^2+y^2)(x-y)(x^4+y^4) (3)(2x+y+z)(y-2x-z)

(1)[(2y+1)(2y-1)]^2 (2)(x+y)(x^2+y^2)(x-y)(x^4+y^4) (3)(2x+y+z)(y-2x-z)
解
[(2y+1)(2y-1)]²
=(4y²-1)²
=16y^4-8y²+1
(x+y)(x²+y²)(x-y)
=(x²-y²)(x²+y²)
=x^4-y^4
(2x+y+z)(y-2x-z)
=[y+(2x+z)][y-(2x+z)]
=y²-(2x+z)²
=y²-4x²-4xz-z²

(1)[(2y+1)(2y-1)]^2
=(4y²-1)²
=16y的4次方-8y²+1

(2) (x+y)(x^2+y^2)(x-y)(x^4+y^4)
=(x-y)(x+y)(x^2+y^2)(x^4+y^4)
=(x²-y²)(x²+y²)(x的4次方+y的4次方)

全部展开

(1)[(2y+1)(2y-1)]^2
=(4y²-1)²
=16y的4次方-8y²+1

(2) (x+y)(x^2+y^2)(x-y)(x^4+y^4)
=(x-y)(x+y)(x^2+y^2)(x^4+y^4)
=(x²-y²)(x²+y²)(x的4次方+y的4次方)
=(x的4次方-y的4次方)(x的4次方+y的4次方)
=x的8次方-y的8次方

(3)(2x+y+z)(y-2x-z)
=[y+(2x+z)][y-(2x+z)]
=y²-(2x+z)²
=y²-4x²-4xz-z²

收起

y (3y^2+8y-3)-6y(3y+2y-1)+9y (y平方+2y)(y平方+2y+2)+1 方程y''=(1+y'*y')/2y的通解 y'=1+y^2 -1+y+20y^2 通分 y+3/y*y-6y+9,1/2y+6,y-1/y*y-9 [(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y y(y-2)²-y(y+3)(y-5) y=1/2 化简求值 y(y-2)²-y(y+3)(y-5) y=1/2 化简求值 y(y-2)²-y(y+3)(y-5) y=1/2 化简求值已知y=-2,求2y-2/y^2-2y+1+y+1/y-1-y的值 (y-2)(y^2-6y-9)-y(y^2-2y-15),其中y=1/2.先化简再求值. 方程y''-4y'+13y=0的通解方程y''=(1+y'*y')/2y的通解 4y²-4y/y²-2y+1÷(y+1/y-1-y-1/y+1)÷(3y+3) [(-2x-y)^2-(2x+y)(2x-y)]÷2y-1/2y 解方程：3y^2-(2y+1)(y-1)=(y-5)(y+1) 解方程3y^2-(2y+1)(y-2)=(y-5)(y-1) 5y∧2-(y-2)(3y+1)-2(y+1)(y-5)