2x/7 +2 + [x-(2x/7 +2)]*2/3-4+20=x,这个方程怎么解?

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2x/7 +2 + [x-(2x/7 +2)]*2/3-4+20=x,这个方程怎么解?
2x/7 +2 + [x-(2x/7 +2)]*2/3-4+20=x,这个方程怎么解?

2x/7 +2 + [x-(2x/7 +2)]*2/3-4+20=x,这个方程怎么解?
把左边的 2x/7 +2 整体移到右边
变成[x-(2x/7 +2)]*2/3-4+20=[x-(2x/7 +2)]
然后把x-(2x/7 +2)看作整体,左边的移到右边得到
-4+20=[x-(2x/7 +2)]*1/3
接下来求解就方便了,两边同时乘以3
x-(2x/7 +2)=48
5x/7=50
x=70

2x/7 +2 + [x-(2x/7 +2)]*2/3-4+20=x
2x/3 + (2x/7 +2)/3=x-16
5x/21=50/3
x=70

两边同乘21得
6x+18*21+14(x-2x/7-2)=21x
去括号 6x+18*21+14x-4x-28=21x
移项,合并 5x=308
系数化为一 x=61又3/5
望采纳啊 用了好长时间算的

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