已知m+n=3,mn=1,求m^2+n^2的值

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已知m+n=3,mn=1,求m^2+n^2的值
已知m+n=3,mn=1,求m^2+n^2的值

已知m+n=3,mn=1,求m^2+n^2的值
m^2+n^2=(m+n)^2-2mn=3^2-2*1=7

（m+n)^2=m^2+n^2+2mn
m^2+n^2=（m+n)^2-2mn
=3^2-2*1=7

7
m²+n²=(m+n)²-2mn=3²-2=7

m^2+n^2=（m+n)^2-2mn=3^2-2=7

原式=(m+n)^2-2mn=7

m+n=3
(m+n)^2=3^2
m^2+n^2+2mn=3^2
m^2+n^2+2*1=9
m^2+n^2=7

因为m^2+n^2=(m+n)^2-2mn
所以原式=3^2-2*1=7

m^2+n^=(m+n)^-2mn=7

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