设Sn是等比数列{an}的前n项和,S3,S9,S6成等差数列. (Ⅰ)求数列{an}的公比q(Ⅱ)求证:a3,a9,a6成等差数列;(Ⅲ)当am,as,(m,s,t∈[1,10],m,s,t互不相等)成等差数列时,求m+s+t的值.

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/28 01:07:10

设Sn是等比数列{an}的前n项和,S3,S9,S6成等差数列. (Ⅰ)求数列{an}的公比q(Ⅱ)求证:a3,a9,a6成等差数列;(Ⅲ)当am,as,(m,s,t∈[1,10],m,s,t互不相等)成等差数列时,求m+s+t的值.
设Sn是等比数列{an}的前n项和,S3,S9,S6成等差数列. (Ⅰ)求数列{an}的公比q
(Ⅱ)求证:a3,a9,a6成等差数列;
(Ⅲ)当am,as,(m,s,t∈[1,10],m,s,t互不相等)成等差数列时,求m+s+t的值.

设Sn是等比数列{an}的前n项和,S3,S9,S6成等差数列. (Ⅰ)求数列{an}的公比q(Ⅱ)求证:a3,a9,a6成等差数列;(Ⅲ)当am,as,(m,s,t∈[1,10],m,s,t互不相等)成等差数列时,求m+s+t的值.
(Ⅱ)∵2a9-a3-a6=2a1q8-a1q2-a1q5=a1q2(2q6-1-q3)=0,
∴2a9=a3+a6,∴a3,a9,a6成等差数列.
(Ⅲ)S3,S9,S6成等差数列⇔2q6-q3-1=0⇔2q6=q3+1⇔2a1q6=a1q3+a1⇔2a7=a4+a1,
∴a1,a7,a4成GP或a4,a7,a1成GP,则m+s+t=12,
同理:a2,a8,a5成GP或a5,a8,a2成GP,
则m+s+t=15,a3,a9,a6成GP或a6,a9,a3成GP,
则m+s+t=18,a4,a10,a7成GP或a7,a10,a4成GP,
则m+s+t=21,∴m+s+t的值为12,15,18,21