x^-2x/x^-1÷{(2x-1/x+1)-x+1}.其中x=(根号2)+1

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x^-2x/x^-1÷{(2x-1/x+1)-x+1}.其中x=(根号2)+1
x^-2x/x^-1÷{(2x-1/x+1)-x+1}.其中x=(根号2)+1

x^-2x/x^-1÷{(2x-1/x+1)-x+1}.其中x=(根号2)+1
原式=(x^-2x)/(x+1)(x-1)÷[(2x-1-x^+1)/(x+1)]
=(x^-2x)/(x+1)(x-1)÷[-(x^-2x)/(x+1)]
=-(x^-2x)/(x+1)(x-1)×(x+1)/(x^-2x)
=1/(x-1)
=1/(√2+1-1)
=√2/2