若2x^2-3xy+2y^2=0,x>0,y>0,x+y/x-y

来源：学生作业帮助网编辑：作业帮时间：2024/04/29 17:18:26

若2x^2-3xy+2y^2=0,x>0,y>0,x+y/x-y
若2x^2-3xy+2y^2=0,x>0,y>0,x+y/x-y

若2x^2-3xy+2y^2=0,x>0,y>0,x+y/x-y
2x^2-3xy+2y^2=0
2(x-y)^2 +xy=0
(x-y)^2 = -xy/2 (1)
2x^2-3xy+2y^2=0
2(x+y)^2 - 7xy =0
(x+y)^2 = 7xy/2 (2)
(2)/(1)
[(x+y)/(x-y)]^2 = -7
(x+y)/(x-y) = √7i