(6-x)^2+(2x)^2=36

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(6-x)^2+(2x)^2=36
(6-x)^2+(2x)^2=36

(6-x)^2+(2x)^2=36
(6-x)²+(2x)²=36
36-12x+x²+4x²=36
5x²-12x=0
x(5x-12)=0
x=0或x=12/5

(6-x)^2=36-12x+x^2
(2x)^2=4x^2
因为(6-x)^2+(2x)^2=36
所以5x^2-12x=0
x=0, x=12/5

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