(x+1/x-1 - x-1/x+1)÷ x/x的平方-1 减去1的2010次幂

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(x+1/x-1 - x-1/x+1)÷ x/x的平方-1 减去1的2010次幂
(x+1/x-1 - x-1/x+1)÷ x/x的平方-1 减去1的2010次幂

(x+1/x-1 - x-1/x+1)÷ x/x的平方-1 减去1的2010次幂
原式={[(x+1)²-(x-1)²]/(x+1)(x-1)}÷[x/(x+1)(x-1)]-1
=[(x+1+x-1)(x+1-x+1)/(x+1)(x-1)]×(x+1)(x-1)/x]-1
=2x/(x+1)(x-1)×(x+1)(x-1)/x-1
=2-1
=1