(1)x(x-2)=(x+3)(x-1)(2)(x+1)(x-3)=x(2x+3)-(1)x(x-2)=(x+3)(x-1) (2)(x+1)(x-3)=x(2x+3)-(x^2-1)

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(1)x(x-2)=(x+3)(x-1)(2)(x+1)(x-3)=x(2x+3)-(1)x(x-2)=(x+3)(x-1) (2)(x+1)(x-3)=x(2x+3)-(x^2-1)
(1)x(x-2)=(x+3)(x-1)(2)(x+1)(x-3)=x(2x+3)-
(1)x(x-2)=(x+3)(x-1) (2)(x+1)(x-3)=x(2x+3)-(x^2-1)

(1)x(x-2)=(x+3)(x-1)(2)(x+1)(x-3)=x(2x+3)-(1)x(x-2)=(x+3)(x-1) (2)(x+1)(x-3)=x(2x+3)-(x^2-1)
(1)x(x-2)=(x+3)(x-1)
x²-2x=x²+2x-3
4x=3
x=3/4
(2)(x+1)(x-3)=x(2x+3)-(x^2-1)
x²-2x-3=x²+3x-x²+1
-2x-3=3x+1
5x=-4
x=-4/5