设数列{an}的前n项和是Sn,Sn满足:S1=a(a≠0),Sn+1 =3Sn+1(n∈N*),数列{bn}满足:bn+2 =2bn+1-bn,且设数列{a­n}的前n项和是Sn,Sn满足:S1=a(a≠0),Sn+1 =3 Sn+1(n∈N*),数列{bn}满足:bn+2 =2bn+1-bn (n∈N*),且b3=3,b5=9.(

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/13 05:19:30

设数列{an}的前n项和是Sn,Sn满足:S1=a(a≠0),Sn+1 =3Sn+1(n∈N*),数列{bn}满足:bn+2 =2bn+1-bn,且设数列{a­n}的前n项和是Sn,Sn满足:S1=a(a≠0),Sn+1 =3 Sn+1(n∈N*),数列{bn}满足:bn+2 =2bn+1-bn (n∈N*),且b3=3,b5=9.(
设数列{an}的前n项和是Sn,Sn满足:S1=a(a≠0),Sn+1 =3Sn+1(n∈N*),数列{bn}满足:bn+2 =2bn+1-bn,且
设数列{a­n}的前n项和是Sn,Sn满足:S1=a(a≠0),Sn+1 =3 Sn+1(n∈N*),数列{bn}满足:bn+2 =2bn+1-bn (n∈N*),且b3=3,b5=9.
(1)分别求数列{a­n}和{bn}的通项公式;
(2)若a=1,若对任意的n∈N*,都有(Sn+1/2)*k≥bn恒成立,求实数k的取值范围.

设数列{an}的前n项和是Sn,Sn满足:S1=a(a≠0),Sn+1 =3Sn+1(n∈N*),数列{bn}满足:bn+2 =2bn+1-bn,且设数列{a­n}的前n项和是Sn,Sn满足:S1=a(a≠0),Sn+1 =3 Sn+1(n∈N*),数列{bn}满足:bn+2 =2bn+1-bn (n∈N*),且b3=3,b5=9.(
(1)
S(n+1)=3Sn+1
S(n+1)+1/2=3(Sn+1/2)
[S(n+1)+1/2]/(Sn+1/2)=3
(Sn+1/2)/(S1+1/2)=3^(n-1)
Sn = -1/2 + (a+1/2)3^(n-1)
an = Sn-S(n-1)
= (2a+1).3^(n-2)
ie
an = a ; n=1
= (2a+1).3^(n-2) ; n>=2
b(n+2) = 2b(n+1)-bn
The aux. equation
x^2-2x+1 =0
x=1
let
bn = A+Bn
b3= A+3B =3 (1)
b5= A+5B = 9 (2)
(2)-(1)
B=3
A=-6
bn =9n-6
(2)
a=1
an =3^(n-1)
Sn= (3^n-1)/2
(Sn+1/2)*k≥bn
(3^n)*k≥ 9n-6
k≥ (9n-6)/3^n
let
f(x)= (9x-6) . 3^(-x)
f'(x) = 3^(-x) [ -(9x-6)ln3 + 9 ]
f'(x) =0
-(9x-6)ln3 + 9 =0
x= (9-6ln3)/(9ln3) =0.243 (max)
max (9n-6)/3^n at n=1
max (9n-6)/3^n = 3/3 =1
ie k≥1

高中数学. 设Sn是数列{an}的前n项和,且Sn=2an+n (1)证明:数列{an-1}是等高中数学. 设Sn是数列{an}的前n项和,且Sn=2an+n (1)证明:数列{an-1}是等比数列 (2)数列{bn}满足bn=1/(2-an),证明:b1+b2+.+bn<1 求:设数列 {an}的前n项和为Sn,数列{Sn}的前n项和为Tn,满足Tn=2Sn一n²,n∈求:设数列 {an}的前n项和为Sn,数列{Sn}的前n项和为Tn,满足Tn=2Sn一n²,n∈N 数列an的前n项和Sn满足:Sn=2n-an 求通项公式 高一数学数列的题目(在线等答案)设等差数列{an}的前n项和为Sn,且a1=2,a3=6,设数列{1/Sn}的前n项和是Tn,求T2013的值(已求出 an=2n,Sn=n^2+n)设数列{an}的前n项和为Sn,an与Sn满足an+Sn=2,令bn=Sn+mS(n+1), 已知数列{an}的前n项和sn满足sn=an^2+bn,求证{an}是等差数列 设Sn是数列an的前n项和,已知a1=1,an=-Sn*Sn-1,(n大于等于2),则Sn= 已知数列{an}的前n项和为Sn,且满足an+2Sn*Sn-1=0,a1=1/2.求证:{1/Sn}是等差数列 已知数列{an}的前n项和为sn,且满足sn=n 设{an}是正项数列,其前n项和Sn满足4Sn=(an-1)(an+3) ,则数列{an}的通项公式= __ 关于等差数列的题设数列{An}的前n项和为Sn,已知A1=1,且满足3Sn^2=An(3Sn-1)(n≥2)(1)求证:数列{1/Sn}是等差数列(2)设bn=Sn/3n+1,求数列{bn)的前n项和n (1)已知数列an的前n项和为sn满足sn=an²+bn,求证an是等差数列(2)已知等差数列an的前n项和为sn,求证数列sn/n也成等差数列 设正整数数列{an}的前n项和Sn满足Sn=1/4(an+1)^2,求数列{an}的通项公式 设正数数列(an)的前n项和Sn满足Sn=1/4(an+1)^2 求 数列(an)的通项公式 在数列{an}中a1=1Sn是其前几项和,当n>=2时,Sn与an满足关系式2Sn^2=an(2Sn-1)证明{1/Sn}是等差数列并求{an}的通项公式(2)设bn=Sn/2n+1,求数列{bn}的前n项和Tn 已知正数数列{an},其前n项和Sn满足10Sn=an^2+5an+6,且a1,a3,a15成等比数列,(1)求数列{an}的通项(通项为an=5n-3) (2)设bn=2/[an*a(n+1)],Sn是数列{bn}的前n项和,求使Sn 1.设{an}为等差数列,Sn为数列{an}的前n项和,已知S7=7,S15=75,Tn为数列{Sn/n}的前n项和,求Tn?2.已知数列{an}的前n项和为Sn(Sn不等于0),且满足an+2Sn*Sn-1=0(n大于等于2),a1=1/2(1).求证:{1/Sn}是等 已知数列{an}满足sn=n/2,sn是{an}的前项和,a2=11.求sn2.设bn=a(n+1)2^n,求数列{bn}的前N和sn=n/2*an 设数列{an}的前n项和为Sn,数列{Sn}的前n项和为Tn,满足Tn=2Sn-n^2,n∈N*.求a1的值以及an的通项公式.