y=sin(x+π/6)+sin(x-π/6)+cosx ,x∈[-π/2,π/2]的值域

判断单调性 y=sin(x-π/6) y=sin(-2x+π/3) Y=sin(x+6/π)+sin(x-6/π)+cosx y=sin(x+π /6）sin(x-π/6）的最小周期是 函数y=2sin(π/3-X)+sin(π/6+X)的最大值 y=12sin(2x+π/6)+5sin(π/3-2x)最大值 y=12sin(2x+π/6)+5sin(π/3-2x)的最大值 函数y=4sin(x+π/6)+3sin(π/3-x)的最大值是多少 y=sin(x-π/6)sin(x+π/3)最小正周期 已知x+y+z=π,证明sin(x+y)+sin(y+z)+sin(z+x)≥sin2x+sin2y+sin2z y=sin(x+π/3)周期 y=|sinπx|的周期 求证sin²x-sin²y=sin(x+y)sin(x-y) 函数y=2sin(2x+π/6) ( -π y=sin(3x-π/6)的导数 已知y=sin(2x+π/6) 求值域 y=3sin(π/6-3x)的周期 函数y=sin(x-π/6)cosx的最小值 y=3sin(4/3x+π/6)周期