{(X+1)/3-(Y+2)/4=0 {(X-3)/4-(Y-3)/12

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{(X+1)/3-(Y+2)/4=0 {(X-3)/4-(Y-3)/12
{(X+1)/3-(Y+2)/4=0 {(X-3)/4-(Y-3)/12

{(X+1)/3-(Y+2)/4=0 {(X-3)/4-(Y-3)/12
你题意没有说完吧!我只能当做一下答案来解了!
(X+1)/3-(Y+2)/4=0 (1)
(X-3)/4-(Y-3)/12=0 (2)
(1)式两边同时乘以12,可得:
4(X+1)-3(Y+2)=0
化简得:4x-3Y=2 (3)
(2)式两边同时乘以36,可得:
9(X-3)-3(Y-3)=0
化简得:9X-3Y=18 (4)
(4)-(3),得:5X=16
X=16/5
将X=16/5带入(3)可得:
Y=18/5

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