x^3-4x^2+5x-2=0因式分解,怎么分啊

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x^3-4x^2+5x-2=0因式分解,怎么分啊
x^3-4x^2+5x-2=0因式分解,怎么分啊

x^3-4x^2+5x-2=0因式分解,怎么分啊
x³-x²-(3x²-5x+2)=0
x²(x-1)-(3x-2)(x-1)=0
(x-1)(x²-3x+2)=0
(x-1)²(x-2)=0
x=1,x=2

x^3-4x^2+5x-2=0
x^3-2x^2-(2x^2-5x+2)=0
x^2(x-2)-(2x-1)(x-2)=0
(x-2)(x^2-2x+1)=0
(x-2)(x-1)^2=0
所以x=1或2

x^3 - 4x^2 + 5x - 2 = 0
( x^3 - 4x^2 + 4x ) + ( x - 2 ) = 0
x( x^2 - 4x + 4 ) + ( x - 2 ) = 0
x( x - 2 )^2 + ( x - 2 ) = 0
( x - 2 )( x^2 - 2x + 1) = 0
( x - 2 )( x - 1 )^2 = 0
所以,x = 1或x = 2.
对否