x的平方+y的平方=2x+y-5\4 求 xy除以x+y

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x的平方+y的平方=2x+y-5\4 求 xy除以x+y
x的平方+y的平方=2x+y-5\4 求 xy除以x+y

x的平方+y的平方=2x+y-5\4 求 xy除以x+y
x^2+y^2=2x+y-5/4
(x^2-2x+1)+(y^2-y+1/4)=0
(x-1)^2+(y-1/2)^2=0
x=1,y=1/2
所以xy/(x+y)=1*1/2/(1+1/2)=1/2/(3/2)=1/3

X=1 Y=1/2 1/3

x^2+y^2=2x+y-5/4
(x^-2x+1)+(y^2-y+1/4)=0
即(x-1)^2+(y-1/2)=0
解之得x =1,y=1/2
代入,xy/(x+y)=1/3

x²+y²=2x+y-5/4
x²-2x+1+y²-y+1/4=0
(x-1)²+(y-1/2)²=0
x=1,y=1/2
所以xy/(x+y)=1/3

(x-1)^2+(y-1/2)^2=0,
x=1,y=1/2

x^2+y^2=2x+y-5/4
(x^-2x+1)+(y^2-y+1/4)=0
即(x-1)^2+(y-1/2)=0
解之得x =1,y=1/2
代入,xy/(x+y)=1/3

x²+y²=2x+y-5/4
x²-2x+1+y²-y+1/4=0
(x-1)²+(y-1/2)²=0
x=1,y=1/2
所以xy/(x+y)=1/3