(1){x+2y+3z=14① {2x+y+z=7②{3x+y+2z=11③(2){x-3/2+3≥x+1①{1-3(x-1)1+2x①{3x+2

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(1){x+2y+3z=14① {2x+y+z=7②{3x+y+2z=11③(2){x-3/2+3≥x+1①{1-3(x-1)1+2x①{3x+2
(1){x+2y+3z=14① {2x+y+z=7②{3x+y+2z=11③
(2){x-3/2+3≥x+1①{1-3(x-1)1+2x①{3x+2

(1){x+2y+3z=14① {2x+y+z=7②{3x+y+2z=11③(2){x-3/2+3≥x+1①{1-3(x-1)1+2x①{3x+2
(1)①×2-②:
3y+5z=21 ④
①×3-③:
5y+7z=31 ⑤
④×5-⑤×3:
z=3,代入前面④ y=2,x=1.
(2)①不对,应该是:
(x-3)/2+3≥x+1
x-3+6≥2x+2
x≤1
② 1-3x+3<8-x,
3x-x>1+3-8
2x>-4,
∴x>-2.
-2<x≤1
(3)①x-5>1+2x
x<-6
②3x+2<4x
4x-3x>2
x>2
没有公共部分.
(4)(√0.01+³√0.001)×√144
=0.1×0.1×12
=0.12
(5)|√2-√5|-|√5+√2|
=√5-√2-(√5+√2)
=√5-√2-√5-√2
=-2√2.