(x-y)[(x+y)^2-xy]+(x-y)[(x-y)^2+xy]

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(x-y)[(x+y)^2-xy]+(x-y)[(x-y)^2+xy]
(x-y)[(x+y)^2-xy]+(x-y)[(x-y)^2+xy]

(x-y)[(x+y)^2-xy]+(x-y)[(x-y)^2+xy]

原式
=(x-y)[(x+y)²-xy+(x-y)²+xy]
=(x-y)[(x+y)²+(x-y)²]
=(x-y)(x²+2xy+y²+x²-2xy+y²)
=(x-y)(2x²+2y²)
=2(x-y)(x²+y²)

解:原式=(x-y)[(x+y)^2-xy+(x-y)^2+xy]=(x-y)(2x^2+2y^2)=2(x-y)(x^2+y^2)


原式
=(x-y)[(x+y)²-xy+(x-y)²+xy]
=(x-y)[(x+y)²+(x-y)²]
=(x-y)(x²+2xy+y²+x²-2xy+y²)
=(x-y)(2x²+2y²)
=2(x-y)(x²+y²)为什么...

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原式
=(x-y)[(x+y)²-xy+(x-y)²+xy]
=(x-y)[(x+y)²+(x-y)²]
=(x-y)(x²+2xy+y²+x²-2xy+y²)
=(x-y)(2x²+2y²)
=2(x-y)(x²+y²)

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