#define N 5 #define f(M) ((N+1)*M) 求x=2*(N+1)+2*f(N+1); 求x的值 最好带运算过程

#define #define N 3 #define Y(n) ((N=1)*n) 则表达式2*（N+Y（5+1))的值是#define N 3 #define Y(n) ((N+1)*n) 则表达式2*（N+Y（5+1))的值是 #define PWM_PCR_PWMENAn(n) ((uint32_t)(((n&0x7) #define N 3 #define Y(n) ( (N+1)*n) 则执行语句:z=2 * (N+Y(5+1));后,z的值为 #define N 2 #define M N+1 #define K M+1*M/2#define N 2#define M N+1#define K M+1*M/2main(){int i;for(i=1;i #define getbit( b,n) (((b) & (1L 下面的程序结果是什么?怎么算?急求答案# include # define M 3# define N M+1# define NN N*N/2void main(){ printf(%d ,NN); printf(%d ,5*NN);} define是什么意思 #define N 5 #define f(M) ((N+1)*M) 求x=2*(N+1)+2*f(N+1); 求x的值 最好带运算过程 define M 5#define N M+M main(){int k;k=N*N*5; printf(%d,k);问结果是多少啊?呜呜,我做的不对, Fibonacci数列函数的定义出错问题...#define M 4 #define N 5#includevoid main(){int i;int fibonacci(int n){if(n ＃define N 3 #define Y(n) ((N+1)*n) 执行Y(5+1)语句后,结果是21不是24,这是怎么回＃define N 3#define Y(n)((N+1)*n)执行Y(5+1)语句后,结果是21不是24,这是怎么回事? #include #define X 5 #define Y X+1 #define Z Y*X/2 main() { int a; a=Y; printf(%d %d ,Z结果为什么是7 5呢,不解, #include #define A 2 #define B(x) x*(A+2) void main() { int a=5; printf(%d ,B(a+1)); } 下列程序运行结果为：#define P 3 #define S(a) P*a*a main() {int ar; ar=S(3+5); printf( %d,ar); } #define P 3 #define S(a) P*a*a main() {int ar; ar=s(3+5) printf( %d,ar) } 这个答案是29,不懂. C语言中 #define N 30 #define IFADOB(A,B) ((A)&&(B,0)) 计算机组成原理习题求解1 Briefly define immediate addressing.2 Briefly define direct addressing.3 Briefly define indirect addressing.4 Briefly define register addressing.5 Briefly define register indirectaddressing.6 Briefly define displace