log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5)
来源:学生作业帮助网 编辑:作业帮 时间:2024/04/29 09:45:47
log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5)
log2(x – 2 ) + 2 = log2(5)
log2(x – 2 ) + 2 = log2(5)
log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5)
原式=log2(5)-log2(x-2)=2.(1)
由logA(M/N)得:
log2[5/(x-2)]=log2(4),即:
5/(x-2)=4,
解得;x=3.25
13/4
原式=log2(5)-log2(x-2)=2...........(1)
由logA(M/N)得:
log2[5/(x-2)]=log2(4),即:
5/(x-2)=4,
解得;x=3.25
log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5)
log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5)
log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1
log2 4+log2 (x+2)怎么算?log2 4+log2 (x+2)=log2 (4x+8)
函数f(x)=(√lx-2l-1)/(log2)(x-1)的定义域?log2,是个单体
log2(2x)*log2(x)=2 x=?
f(x)=log2(x/8)*log2(2/x)
求导 y=log2(x^2)-log2(x)
求解log2(3x)=log2(2x+1)
解方程log2(2-x)=log2(x-1)+1
解2log2^(x-5)=log2^(x-1)+1
函数f(x)=(√lx-2l-1)/log2(x-1)的定义域
解方程log2(x+14)-log2(x+6)=3-log2(x+2)
[log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204
|2x-log2^x|
|[log2(x)]^2-3log2(x)+1|
化简:(log2(x/4))*(log2(x/2))
不等式[log2(-x)]2>=log2(x2)的解集是