数学化简【a+1分之1 + a-1分之1】除以a²-2a+1分之2a

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数学化简【a+1分之1 + a-1分之1】除以a²-2a+1分之2a
数学化简【a+1分之1 + a-1分之1】除以a²-2a+1分之2a

数学化简【a+1分之1 + a-1分之1】除以a²-2a+1分之2a

[1/(a+1)+1/(a-1)]÷2a/(a²-2a+1)
=[(a-1)/(a-1)(a+1)+(a+1)/(a+1)(a-1)]×[(a-1)²/2a]
=[(a-1+a+1)/(a+1)(a-1)]×[(a-1)²/2a]
=[2a/(a-1)(a+1)]×[[(a-1)²/2a]
=(a-1)/(a+1)

(a-1)/(a+1)

(a-1)/(a+1)

{[1/(a+1)]+[1/(a-1)]}/[2a/(a²-2a+1)]
={[(a-1)+(a+1)]/[(a+1)(a-1)]/[2a/(a-1)²]
={2a/[(a+1)(a-1)]}×(a-1)²/(2a)
=(a-1)/(a+1)

=【(a+1)(a-1)分之2a】乘以2a分之(a-1)的平方
=(a+1)分之(a-1)