解log(2x – 3)(x2－3)＞0 (2x-3)是底数.

解log(2x – 3)(x2－3)＞0 (2x-3)是底数. log(2x – 3)(x2－3)＞0求解 解不等式log(0.5)(x2-5x-6)＞log(2)(1/2(x+6)) log(2)(x-1)=log(2)(x2+2x-3)求解!要步骤!谢谢 解方程3log(x)4+2log(4x)4+3log(16x)4=0 求y=log½(3+2x－x2)的值域 解方程[log(a)(x-1)]-[log(a)(2x-3)]=log(a)(1/3-x),(a＞0,且a≠1). log(2)(x)log(2)(4x)-3log(2)(x)-12=0 (log(2)(x))^3-4(log(4)(x))^2+log(16)(x)=0 已知log（2）[log（3)(log(4) x)] = log(3) [log(4) (log(2) y)]=0,求x+y的值 log(9)x+log(x^2)3=1的解为?原方程可可化为log(3 ²)x+log(x)²3=1 ,∴1/2*log(3)X+1/2*log(x)3=1,∴[log(3)x]²-2log(x)3+1=0,即[log(3)x-1]²=0请问这里的[log(3)x]²-2log(x)3+1=0是怎么推出来的,刚学基础不好, 已知log(2){log(3)[log(4)(x)]}=5^0,则x=? 解方程3log(2)(x)+2log(x)(2)-5=0 解[log(x-1)]²+2log(x-1)-3=0 设函数f (x)＝x2－x＋b拜托各位了 3Q设函数f (x)＝x2－x＋b,已知log 2f (a)＝2,且f (log 2a)＝b (a>0且a≠1),(1) 求a,b的值；(2) 试在f (log 2x)>f (1)且log 2f (x) log(x+3)(x2+3x)=2,求实数x的值 log(x-2)(-x2+3x+18)中 实数x的取值范围.RT. 函数f(x)=log(x2-2x+3)定义域 值域 单调区间