carl has $9 more than david does.hilbert has 1/3 of the amout of carl.if they have a total amout of $61,how much does each of them have?

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carl has $9 more than david does.hilbert has 1/3 of the amout of carl.if they have a total amout of $61,how much does each of them have?
carl has $9 more than david does.hilbert has 1/3 of the amout of carl.if they have a total amout of $61,how much does each of them have?

carl has $9 more than david does.hilbert has 1/3 of the amout of carl.if they have a total amout of $61,how much does each of them have?
Let $x be the amount of Carl has,$(x-9) be the amount of David has and $(x/3) be the amount of Hibert.
x+(x-9)+(x/3)=61
7x-27=183
7x=210
x=30
Carl has $30,David has $21 and Hibert has $10

  Carl 的钱比David多9 美元,Hilbert的钱是Carl的1/3,如果他们三人一共有61美元,他们三人各有多少美元?
设Carl 有x美元
 ∴David有(x-9)美元
  Hilbert有(x/3)美元
 ∴x+(x-9)+(x/3)=61
  7x=210
  x=30
 ∴x-9=30-9=21
  x/3=30...

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  Carl 的钱比David多9 美元,Hilbert的钱是Carl的1/3,如果他们三人一共有61美元,他们三人各有多少美元?
设Carl 有x美元
 ∴David有(x-9)美元
  Hilbert有(x/3)美元
 ∴x+(x-9)+(x/3)=61
  7x=210
  x=30
 ∴x-9=30-9=21
  x/3=30÷3=10
答:Carl 有30美元,David有21美元,Hilbert有10美元

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