实数x1,x2满足x1^2-6(x1)+2=0和x2^2-6(x2)+2=0,求x2/x1+x1/x2

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实数x1,x2满足x1^2-6(x1)+2=0和x2^2-6(x2)+2=0,求x2/x1+x1/x2
实数x1,x2满足x1^2-6(x1)+2=0和x2^2-6(x2)+2=0,求x2/x1+x1/x2

实数x1,x2满足x1^2-6(x1)+2=0和x2^2-6(x2)+2=0,求x2/x1+x1/x2
实数x1,x2满足x1^2-6(x1)+2=0和x2^2-6(x2)+2=0,
则,x1,x2是方程x^2-6x+2=0的两个根
所以,x1+x2=6,x1x2=2
x2/x1+x1/x2
=(x2^2+x1^2)/x1x2
=[(x1+x2)^2-2x1x2]/x1x2
=(x1+x2)^2/x1x2-2
=36/2-2
=18-2
=16

这个题出有问题 如果再加条件x1不等于x2
通分x1,x2相当于x^2-6x+2=0的两个根x1+x2=-b/2a x1x2=c/2a (x1+x2)/x1x2 3/1=3